Jason Rhinelander 7d46c6f60d Make is_template_base_of ignore cv qualification
`is_template_base_of<T>` fails when `T` is `const` (because its
implementation relies on being able to convert a `T*` to a `Base<U>*`,
which won't work when `T` is const).

(This also agrees with std::is_base_of, which ignores cv qualification.)
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